In the prior section, we discovered that resolving two nearby frequencies depends crucially on the rectangular window and its corresponding sinc
Discrete Fourier Transform (DFT). However, our two nearby signals had equal amplitudes. What happens when this is no longer the case? The figure below shows the DFT of two nearby signals where one has ten times the amplitude.
from __future__ import division
from scipy import signal
# some useful functions
def dftmatrix(Nfft=32,N=None):
'construct DFT matrix'
k= np.arange(Nfft)
if N is None: N = Nfft
n = arange(N)
U = matrix(exp(1j* 2*pi/Nfft *k*n[:,None])) # use numpy broadcasting to create matrix
return U/sqrt(Nfft)
def db20(W,Nfft=None):
'Given DFT, return power level in dB'
if Nfft is None: # assume W is DFT
return 20*log10(abs(W))
else: # assume time-domain passed, so need DFT
return 20*log10(abs( fft.fft(W,Nfft)/sqrt(Nfft) ) )
fs = 64 # sampling frequency
t = arange(0,2,1/fs)
f = 10 # one signal
deltaf = 2.3 # second nearby frequency
Nf = 512
fig,ax = subplots(2,1,sharex=True,sharey=True)
fig.set_size_inches((9,4))
x=10*cos(2*pi*f*t) + 10*cos(2*pi*(f+deltaf)*t) # equal amplitudes
X = fft.fft(x,Nf)/sqrt(Nf)
ax[0].plot(linspace(0,fs,len(X)),abs(X),'-o',ms=3.)
ax[0].set_ylabel(r'$|X(k)|$',fontsize=18)
ax[0].set_xlim(xmax = fs/2)
ax[0].grid()
ax[0].text(0.5,0.5,'Same amplitudes',
transform=ax[0].transAxes,
backgroundcolor='Lightyellow',
fontsize=16)
x=cos(2*pi*f*t) + 10*cos(2*pi*(f+deltaf)*t) # one has 10x the amplitude
X = fft.fft(x,Nf)/sqrt(Nf)
ax[1].plot(linspace(0,fs,len(X)),abs(X),'-o',ms=3.)
ax[1].set_ylabel(r'$|X(k)|$',fontsize=18)
ax[1].set_xlabel('Frequency (Hz)',fontsize=18)
ax[1].set_xlim(xmax = fs/2)
ax[1].grid()
ax[1].text(0.5,0.5,'Different amplitudes',
transform=ax[1].transAxes,
backgroundcolor='lightyellow',
fontsize=16)
ax[1].annotate('Smaller signal',
fontsize=12,xy=(f,abs(X)[int(f/fs*Nf)]),
xytext=(2,15),
arrowprops={'facecolor':'m','alpha':.3});
# fig.savefig('figure_00@.png', bbox_inches='tight', dpi=300)
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In the figure above, the top plot shows the two peaks of nearby signals when they both have the same amplitude. The bottom plot shows the case where the higher frequency signal has ten times the amplitude. Note that the two frequencies are no longer resolvable because the weaker signal (smaller amplitude) has descended into the sidelobes of the stronger one. Thus, we need more than just longer sampling durations and denser DFTs to resolve these signals. This is where windows (sometimes called tapers) come in.
A window is a function that is multiplied sample-by-sample against the input signal (i.e. element-wise). For example, given an input signal, $s_n$, and a window, $w_n$, the new windowed signal is,
$$ y_n = s_n w_n $$known in vector notation as the Hadamard product,
$$ \mathbf{y} = \mathbf{w} \odot \mathbf{s} $$The following figure compares the the rectangular and triangular windows applied to an input sinusoid.
fig,axs = subplots(2,1)
fig.set_size_inches((10,5))
Nf = 128
nsamp = 64
window = signal.triang(nsamp)
rectwin = ones(nsamp)
ax = axs[0]
ax.plot(arange(nsamp),window,'m-o',label='triangular')
ax.stem(arange(nsamp),rectwin,basefmt='b-',label='rectangular')
ax.set_ylim(ymax = 1.1,ymin=-0.1)
ax.legend(loc=0)
x=array(dftmatrix(64,64)[:,5].real).flatten() # convert to numpy array
n = arange(len(x))
window = signal.triang(len(x))
ax = axs[1]
ax.plot(n,x,'-o',label='signal',ms=3.,alpha=0.3)
ax.plot(n,window*x,'-or',label='windowed\nsignal',ms=5.)
ax.set_ylabel('Amplitude',fontsize=16)
ax.set_xlabel('sample index',fontsize=16)
ax.legend(loc=0)
ax.grid()
ax2 = ax.twinx()
ax2.fill_between(n,window,alpha=0.2,color='m')
ax2.set_ylabel('Window function',fontsize=16);
# fig.savefig('figure_00@.png', bbox_inches='tight', dpi=300)
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In the figure above, the top plot shows the $w_n$ sequences for the rectangular and triangular windows. The bottom plot shows the input signal before (light blue line) and after (red line) applying the triangular window. The amplitudes are noted on the vertical scale on the left. The triangular window is drawn in the background with scale noted on the right side. Basicially, the red line is the product of the blue line and the pink background window function. As shown, because the triangular window slopes to zero at the beginning and at the end, the amplitude of the input signal drops away from the middle. This means that we lose precious signal energy at the start and end of the signal. We certainly want something in exchange for this!
The following figure shows the two input signals with rectangular, triangular, and Hamming windows applied.
Nf = 512
fig,ax = subplots(3,1,sharex=True,sharey=True)
fig.set_size_inches((10,6))
x=cos(2*pi*f*t) + 10*cos(2*pi*(f+deltaf)*t)
X = fft.fft(x,Nf)/sqrt(Nf)
ax[0].plot(linspace(0,fs,len(X)),db20(X),'-o',ms=3.)
ax[0].set_xlim(xmax = fs/2)
ax[0].grid()
ax[0].text(0.5,0.5,'rectangular window',
transform=ax[0].transAxes,
backgroundcolor='lightyellow',
fontsize=16)
ax[0].annotate('Smaller signal',
fontsize=12,xy=(f,db20(X)[int(f/fs*Nf)]),
xytext=(1,30),
arrowprops={'facecolor':'m'})
w = signal.triang(len(x))
X = fft.fft(x*w,Nf)/sqrt(Nf)
ax[1].plot(linspace(0,fs,len(X)),db20(X),'-o',ms=3.)
ax[1].set_xlim(xmax = fs/2)
ax[1].grid()
ax[1].text(0.5,0.5,'triangular window',
transform=ax[1].transAxes,
backgroundcolor='lightyellow',
fontsize=16)
ax[1].annotate('Smaller signal',
fontsize=12,xy=(f,db20(X)[int(f/fs*Nf)]),
xytext=(1,30),
arrowprops={'facecolor':'m'})
w = signal.hamming(len(x))
X = fft.fft(x*w,Nf)/sqrt(Nf)
ax[2].plot(linspace(0,fs,len(X)),db20(X),'-o',ms=3.)
ax[2].set_xlabel('Frequency (Hz)',fontsize=18)
ax[2].set_xlim(xmax = fs/2)
ax[2].grid()
ax[2].set_ylim(ymin=-20)
ax[2].text(0.5,0.5,'Hamming window',
transform=ax[2].transAxes,
backgroundcolor='lightyellow',
fontsize=16)
ax[2].annotate('Smaller signal',
fontsize=12,xy=(f,db20(X)[int(f/fs*Nf)]),
xytext=(1,30),
arrowprops={'facecolor':'m'});
# fig.savefig('figure_00@.png', bbox_inches='tight', dpi=300)
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To enhance detail, the figure above shows the the $20\log_{10} | X_k |$ of the DFT of the input signal with noted windows applied on the same scale. The top plot shows the rectangular window and we can barely make out the smaller signal in the sidelobes of the dominant larger signal. The middle plot shows the triangular window and we can see that there is definitely something peeking out from the sidelobes, but we can see this most clearly using the Hamming window (bottom plot), which shows a peak at the nearby frequency. Note that the width of the mainlobe widened as the second weaker signal emerged from the sidelobes of the stronger signal. This is one of the trade-offs involved when using windows for spectral analysis.
In this section, we demonstrated that window functions can help resolve nearby frequencies that have different amplitudes. As the plots showed, we traded precious signal energy for resolution, but we need a systematic framework for evaluating different window functions. This framework will be the topic of our next section.
As usual, the corresponding IPython notebook for this post is available for download here.
Comments and corrections welcome!